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[求助] 65nm下电容的失配问题

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发表于 2010-12-24 22:56:27 | 显示全部楼层 |阅读模式

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最近拿到一个foundry 65nm的工艺,但是工艺说明文档上并没有写电容的匹配精度,请问一般在65nm工艺下电容的失配随面积是怎样变化的呢?

这个工艺提供的电容是长条形的,W固定为0.1um,只能改变L和finger
发表于 2010-12-25 07:51:11 | 显示全部楼层
本帖最后由 fhchen2002 于 2010-12-25 10:28 编辑

I guess it is so called "vertical parallel plate capacitor."
I suppose it (the vertical plates, the vertical walls) is built by the mutiple via and metal layers of the process technology.
The higher number of interconnect layers (usually associated with more advanced technology nodes), the higher unit capacitance.

Refer to the following URL for discussions overseas.

http://www.designers-guide.org/Forum/YaBB.pl?num=1146378302

The original IEEE JSSC paper is attached for your reference reference.

As a matter of fact foundries do have matching data (and technical documents) about this type of capacitors.
I used such type of capacitor since 2001 (0.18-um node).
I know TSMC and Global Foundry provide mismatch data of such type of capacitors.t
Sorry, I cannot attach their data to this site (legal issue).
Simply ask the customer support engineers of foundries to get these technical reports.

Capacity Limits and Matching Properties of Integrated Capacitors.pdf

650.68 KB, 下载次数: 740 , 下载积分: 资产 -2 信元, 下载支出 2 信元

IEEE JSSC Paper

发表于 2010-12-25 11:18:06 | 显示全部楼层
本帖最后由 fhchen2002 于 2010-12-25 17:40 编辑

More inputs
The capacitance per unit area is actually a function of the following:
1. Length of metal stripes (L)
2. Spacing of metal stripes on the same layer (S)
3. Width of the metal stripes (W)
4. Number of parallel metal stripes on the same layer (so called "M", i.e., the number of fingers)
5. Number of metal layers that can be used in the capacitor layout

Area of the capacitor layout ~= L x [(M-1) x S + M x W]

Specifying S in the capacitor layout is not straightforward.  (Not simply to use min. spacing)
Just imagine the the vertical walls are built by stripes of metal and vias.
In between the vias are atually filled by IMD (inter-metal-dielectrics), which is void (in terms of conducting material).
So the conductor (plate) surface is not continuous.
Even more, it can be considered zig-zag.

So specifying S by the minimum DR is probably not the best approach.
Making S >> minimum spacing (e.g., S = 3 x min. metal-to-metal spacing) between metal stripes improves the uniformity, at the cost of reduced capacitance per unit-area.

I guess, there would be a good number of S between min. DR allows and 3 times this number, which give good tradeoff between layout area and capacitor matching perfomance.


Other notes
  • Avoid using M1 as the starting conducting layer, since M1-to-substrate/bulk parasitic capacitance is relatively a large percentage of the total capacitance.
  • Use top metal layer to increase the capacitance per unit area.  M_top is thicker and creates more "side-wall" capacitance.  (Since M_top spacing is also a larger number compared to those in lower metal layers.)  If necessary, rotate the M_top stripes by 90 degrees.  Overlay the (rotated) M_top fingers on top of lower-layer layout.
  • Depending on how high your vertical wall stacks up, keep the neighborhood layout components at least two times the distance from the capacitor, such that the unwanted signal coupling is reduced.  A simple rule of thumbs: # of metal layer = N, the distance you want to keep your non-relevant components away from the edge of the capacitor = 2 N um.  So you see, this capacitor layout is not too area efficient.
发表于 2010-12-25 12:22:20 | 显示全部楼层
楼上很犀利啊
发表于 2010-12-25 17:05:38 | 显示全部楼层
回复 3# fhchen2002


    what is the purpose of "If necessary, rotate the M_top stripes by 90 degrees.  Overlay the (rotated) M_top fingers on top of lower-layer layout" ? is this increase value per unit?
发表于 2010-12-25 17:34:22 | 显示全部楼层
本帖最后由 fhchen2002 于 2010-12-25 17:43 编辑

These are the assumptions:
  • You want to specify minimum width (of all conducting layers) to maximize the capacitance per unit area.
  • You probably don't want to use minimum spacing in the lower conducting layers, due to the reason mentioned in my previous reply e-mail.


Reminder: the M_top width and spacing are different from those of lower layers.
For example, the following numbers (in microns) are what you want to use in this layout:
                        W    S
M_top                   1.1    2.0
M_2 - M_top-1     0.4    0.6

When you put M_top metal stripes on top of M_top-1 metal stripes (non-rotated fashion), you will find that due to (width + spacing) mismatches, some of the M_top stripes do not find vias that interconnect to underneath M_top-1 stripes.

No vias means "flux leakage."
The highest density of vias means "the minimum amount of flux leakage."
Rotating the top metal stripes by 90 degrees and let M_top stripes find vias to connect to M_top-1 stripes is what I think a compromised (not the best) solution to address the flux leakage issue.

Yes, it ends up increase the capacitance per unit area somehow.
发表于 2010-12-27 12:55:58 | 显示全部楼层
高人!
发表于 2010-12-27 15:19:45 | 显示全部楼层
高人啊,很强大
 楼主| 发表于 2010-12-28 19:38:32 | 显示全部楼层
谢谢fhchen2002的解答,我另外还有个问题是这个工艺线提供了多种采用多层金属实现MOM电容的structure, 比如M1~M5,M1~M6,M2~M5,M2~M6,M3~M6,M4~M6等等,采用的金属层数与电容的匹配之间有没有什么关系呢,是不是采用的层数越多匹配就越好呢
发表于 2010-12-28 22:10:16 | 显示全部楼层
The more number of metal layers you use, the more capacitance per unit area.
When you gain more capacitance per unit area, you may want to enlarge the S between fingers to improve the matching property, at the cost of slightly reduced capacitance per unit area.

Compared to M2-M6 capacitor, M3-M6 capacitor (with the same area) has less parasitc capacitance to bulk/substrate.
Remember, OD and poly (which form the MOS devices) are right above the well/substrate.
So using M3-M6 to form the flux capacitor (aka vertical capacitor) creates less noise coupling to active devices.

It is a matter of trading-off area efficiency and noise coupling.
I don't think capacitance matching is directly relevant in this regard.
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