可是我看到某位高手是这么做的:先对100MHz工作时钟分频,产生1MHz的时钟,再对1MHz的时钟计数来实现10ms的延时。综合时出现下面的警告:
Warning: Found 1 node(s) in clock paths which may be acting as ripple and/or gated clocks -- node(s) analyzed as buffer(s) resulting in clock skew
Info: Detected ripple clock "INT_Control:INT_Control_inst|clk_1M" as buffer