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[求助] Cascold电流镜

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发表于 2022-3-20 14:13:51 | 显示全部楼层 |阅读模式
50资产

Cascold电流镜 输出电压下降,哪个管子先进入线性区,为什么?谢谢
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M2 will enter the triode region first. As M2 drain voltage (Vd2=Vout) drops, and its gate voltage (Vg2=Vin) is constant, two things should happen: 1) Drain voltage of M1 is pinned as VGS2 is constant (Vin-Vth) --> So M1 is still maintained in SAT region. 2) VGD2 should be smaller than Vth, so if the difference increased beyond Vth (as Vout drops, Vin-Vout increases) then M2 will enter Triode reg ...
发表于 2022-3-20 14:13:52 | 显示全部楼层
M2 will enter the triode region first.

As M2 drain voltage (Vd2=Vout) drops, and its gate voltage (Vg2=Vin) is constant, two things should happen:

1) Drain voltage of M1 is pinned as VGS2 is constant (Vin-Vth) --> So M1 is still maintained in SAT region.
2) VGD2 should be smaller than Vth, so if the difference increased beyond Vth (as Vout drops, Vin-Vout increases) then M2 will enter Triode region.

Hope this helps  
发表于 2022-3-20 15:23:53 | 显示全部楼层
本帖最后由 vaeping123 于 2022-3-20 15:27 编辑

拉扎维P129页
假设下面的管子M1先进入线性区,Vds减小而Vgs1是不变的,那么Id1会下降。Id1和Id2下降但是Vd1下降说明VGs2是上升的。显然不成立,所以M2先进入线性区。

 楼主| 发表于 2022-3-21 20:10:39 | 显示全部楼层


vaeping123 发表于 2022-3-20 15:23
拉扎维P129页
假设下面的管子M1先进入线性区,Vds减小而Vgs1是不变的,那么Id1会下降。Id1和Id2下降但是Vd1 ...


谢谢!
 楼主| 发表于 2022-3-21 20:11:52 | 显示全部楼层


MustafaSami 发表于 2022-3-20 18:58
M2 will enter the triode region first.

As M2 drain voltage (Vd2=Vout) drops, and its gate voltage ( ...


Thanks for your help!
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