后端标准单元库lib的疑问

亭ting

标准单元库的.lib文件中，给出了一个internal power，这个包括switch power和hidden power.有么有大神知道这个究竟怎么算的，它的单位是什么呐？我看到有power信息记录文件，里面内容是这样的：（1）INV的：
* Cell=INVM0R_st Pin=Z RelatedPin=A RelatedPGPin=VDD Type=combinational Direction=rise_transition When= Deck= Vector_space=FR Vector_used=10
    - Leakage_state =
    - Leakage_value =
    - Raw_equation  = (((-Q(VDD))*(VDD(VDD)-GND(GND))*0.5-(((Cload(Z)*(_ecsmRailVdd - _ecsmRailGnd))*(_ecsmRailVdd - _ecsmRailGnd)*0.5))))/capacitance_unit

    - Eval_equation = (((1.39903e-11)*(0.3-0)*0.5-(((2.38337e-15*(0.299988-4.63108e-05))*(0.299988-4.63108e-05)*0.5))))/1e-12
    - Value         = 2.09844


（2）NAND2的：
* Cell=ND2M0R_st Pin=Z RelatedPin=A RelatedPGPin=VDD Type=combinational Direction=rise_transition When= Deck= Vector_space=FxR Vector_used=110
    - Leakage_state =
    - Leakage_value =
    - Raw_equation  = ((((-Q(VDD))*(VDD(VDD)-GND(GND))*0.5)*2.0-((((Cload(Z)*(_ecsmRailVdd - _ecsmRailGnd))*(_ecsmRailVdd - _ecsmRailGnd)*0.5)*2.0))))/capacitance_unit

    - Eval_equation = ((((1.45894e-11)*(0.3-0)*0.5)*2.0-((((1e-15*(0.299988-0.000185172))*(0.299988-0.000185172)*0.5)*2.0))))/1e-12
    - Value         = 4.37673

有的没有上面的2，会是这样的
* Cell=ND2M0R_st Pin=Z RelatedPin=A RelatedPGPin=VDD Type=combinational Direction=rise_transition When= Deck= Vector_space=FxR Vector_used=110
    - Leakage_state =
    - Leakage_value =
    - Raw_equation  = (((-Q(VDD))*(VDD(VDD)-GND(GND))*0.5-(((Cload(Z)*(_ecsmRailVdd - _ecsmRailGnd))*(_ecsmRailVdd - _ecsmRailGnd)*0.5))))/capacitance_unit

    - Eval_equation = (((1.45894e-11)*(0.3-0)*0.5-(((1e-15*(0.299988-0.000185172))*(0.299988-0.000185172)*0.5))))/1e-12
    - Value         = 2.18836


请大家帮忙，解释一下。