请教44B0的256色LCD显示例子

pettymiao

我用ADS写了一个简单的LCD显示正方形如下：

unsigned int LcdBuffer[240][640/4];

unsigned int *pBuf=(unsigned int *)LcdBuffer;
   main()

  {   int i,j;

rPCONC=0x0f00ff54;   
rPCOND= 0xaaaa;
rLCDCON1=(0x0)|(2<<5)|(0<<7)|(0x3<<8)|(0x3<<10)|(4<<12);
rLCDCON2=(240-1)|((640*3/8-1)<<10)|(14<<21);
rLCDSADDR1=(0X3<<27)|(((unsigned int)LcdBuffer>>22)<<21)|(((unsigned int)LcdBuffer>>1)&0x1fffff);
rLCDSADDR2=((((unsigned int)LcdBuffer +(640*320))>>1))|(13<<21)&0x1fffff;   
rLCDSADDR3=(640/2)|(0<<9);
rREDLUT  =0xfdb96420;
rGREENLUT=0xfdb96420;
rBLUELUT =0xfb40;
  rDITHMODE=0x0;
rDP1_2 =0xa5a5;      
rDP4_7 =0xba5da65;
rDP3_5 =0xa5a5f;
rDP2_3 =0xd6b;
rDP5_7 =0xeb7b5ed;
rDP3_4 =0x7dbe;
rDP4_5 =0x7ebdf;
rDP6_7 =0x7fdfbfe;

rLCDCON1=(0x1)|(2<<5)|(0<<7)|(0x3<<8)|(0x3<<10)|(4<<12); //使能显示
    for(i=0;i<(640*240/4);i++)   //绘背景
    {
       *pBuf++=(0x0<<24)+(0x0<<16)+(0x0<<8)+0x0;
    }
     for(i=0;i<100;i++)          //绘正方形
     {
        for(j=0;j<100;j++)
        {
           LcdBuffer[100+i][100+j]=0xe03;
        }
   }

程序编译通过了，但256彩屏没有一点显示，请问错在哪里啊，欢迎QQ 113162523 指导，谢谢