| 
 | 
 
 
马上注册,结交更多好友,享用更多功能,让你轻松玩转社区。
您需要 登录 才可以下载或查看,没有账号?注册  
 
×
 
    
    
            
             
            
            
            
 
Suppose the in-phase signal current sources, I i n l and Iin2, are 
pushed into the class-AB output stage. As a result, the current 
of the P-channel class-AB transistor, M20, increases while the 
current in the N-channel class-AB transistors, M19, decreases 
by the same amount. Consequently, the gate-voltages of both 
the output transistors move up. Thus the output stage pulls 
a current from the output node. This action continues until 
the current through the P-channel class-AB transistor is equal 
to 1t,7. Now, the current of the P-channel output transistor 
is kept at a minimum value, which can be set by W over L 
ratios of the class-AB control transistors. Note that the current 
through the N-channel output transistor is still able to increase. 
 
 
这是“A Compact Power-Efficient 3 V CMOS 
Rail-to-Rail Input/Output Operational 
Amplifier for VLSI Cell Libraries” 
里的一段话,描述了Class AB的工作原理,我不明白的是他说这个两个电流是“in-phase”的,那么电流lin1 lin2他们不符合基尔霍夫定律啊。。。 
其次他说这个电流push into the class-AB transistor会导致PMOS管里的电流增大,这是为什么,为什么不是NMOS管里的电流增加? 
 
求各位高人解答 |   
 
 
 
 |