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发几verilog基础题

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发表于 2008-12-17 19:05:31 | 显示全部楼层 |阅读模式

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1. Is this a valid, synthesizable, use of a for loop?

module for_loop();

reg [8:0] A, B;
integer i;
parameter N=8;
always@(B)
begin
for (i=1; i<=N; i=i+1)
A[i-1]=B;
A[N] = A[N-1];
end
endmodule

2. Assuming the code above is synthesizable, Which of the following continuous assignment statements would have the closest meaning?

A. assign A = B << 1;
B. assign A = B <<< 1;
C. assign A = B >> 1;
D. assign A = B >>> 1;

3. If the following logic is built exactly as described, which test vector sensitizes a stuck-at-0 fault at "e" and propagates it to the output "g".


module (a, b, c, d, e, f, g);
input a, b, c, d;
output e, f, g;

assign e = a & b;
assign f = c ^ e;
assign g = d | f;

endmodule

A. {a, b, c, d} = 4’b0010;
B. {a, b, c, d} = 4’b1100;
C. {a, b, c, d} = 4’b1111;
D. {a, b, c, d} = 4’b0101;
E. None of the above

4. Consider the following two test fixtures.

// Fixture A
parameter delay1 =
parameter delay2 =
initial
begin
B = 1’b0;
#20 A = 1’b1;
#delay1 A = 1’b0;
#delay2 B = 1'b1;
end

// Fixture B
initial
fork
B = 1’b0;
#20 A = 1’b1;
#40 A = 1’b0;
#60 B = 1’b1;
join

For these two fixtures to produce the same waveforms, delay1 and delay2 have to be set
as follows:

A. delay1 = 40; delay2 = 60;
B. delay1 = 30; delay2 = 20;
C. delay1 = 30; delay2 = 30;
D. delay1 = 20; delay2 = 20;
E. None of these are correct

5. In verification, most of the effort should be applied at the system (complete chip) level. Which of the following statements gives the best reason as to why?


A. Most of the bugs in a design are in the netlist wiring it together.
B. Most of the bugs in a design are due to poorly understood interactions between different modules.
C. This is the fastest way to verify the individual modules that make up the design.
D. Most of the bugs in a design occur because of poorly designed interfaces, e.g. buses.
E. None of the above are remotely a good reason.

6. Consider the following specify block:

specify
specparam A0spec = 1 : 2 : 3;
specparam A1spec = 2 : 3 : 4;
(a => b) = (A0spec, A1spec);
endspecify

This is defining the following:

A. Rising, falling and steady delay from input a to output b of 1, 2, and 3 ns respectively when a is 0, and 2, 3, and 4 ns when a is 1.
B. Minimum, typical and maximum delay from input a to output b of 1, 2, and 3 ns on a rising edge at B, and 2, 3 and 4 ns on a falling edge.
C. Non-blocking assignment of a to b with minimum, typical and maximum delay of 1, 2 and 3ns.
D. Setup time requirements for the flip-flop with output B.
发表于 2008-12-17 21:31:06 | 显示全部楼层
1. Is this a valid, synthesizable, use of a for loop?
module for_loop();
reg [8:0] A, B;
integer i;
parameter N=8;
always@(B)
begin
for (i=1; i<=N; i=i+1)
A[i-1]=B;
A[N] = A[N-1];
end
endmodule
2. Assuming the code above is synthesizable, Which of the following continuous assignment statements would have the closest meaning?
A. assign A = B << 1;
B. assign A = B <<< 1;
C. assign A = B >> 1;
D. assign A = B >>> 1;
3. If the following logic is built exactly as described, which test vector sensitizes a stuck-at-0 fault at "e" and propagates it to the output "g".
module (a, b, c, d, e, f, g);
input a, b, c, d;
output e, f, g;
assign e = a & b;
assign f = c ^ e;
assign g = d | f;
endmodule
A. {a, b, c, d} = 4’b0010;
B. {a, b, c, d} = 4’b1100;
C. {a, b, c, d} = 4’b1111;
D. {a, b, c, d} = 4’b0101;
E. None of the above
4. Consider the following two test fixtures.
// Fixture A
parameter delay1 =
parameter delay2 =
initial
begin
B = 1’b0;
#20 A = 1’b1;
#delay1 A = 1’b0;
#delay2 B = 1'b1;
end
// Fixture B
initial
fork
B = 1’b0;
#20 A = 1’b1;
#40 A = 1’b0;
#60 B = 1’b1;
join
For these two fixtures to produce the same waveforms, delay1 and delay2 have to be set
as follows:
A. delay1 = 40; delay2 = 60;
B. delay1 = 30; delay2 = 20;
C. delay1 = 30; delay2 = 30;
D. delay1 = 20; delay2 = 20;
E. None of these are correct
5. In verification, most of the effort should be applied at the system (complete chip) level. Which of the following statements gives the best reason as to why?
A. Most of the bugs in a design are in the netlist wiring it together.
B. Most of the bugs in a design are due to poorly understood interactions between different modules.
C. This is the fastest way to verify the individual modules that make up the design.
D. Most of the bugs in a design occur because of poorly designed interfaces, e.g. buses.
E. None of the above are remotely a good reason.
6. Consider the following specify block:
specify
specparam A0spec = 1 : 2 : 3;
specparam A1spec = 2 : 3 : 4;
(a => b) = (A0spec, A1spec);
endspecify
This is defining the following:
A. Rising, falling and steady delay from input a to output b of 1, 2, and 3 ns respectively when a is 0, and 2, 3, and 4 ns when a is 1.
B. Minimum, typical and maximum delay from input a to output b of 1, 2, and 3 ns on a rising edge at B, and 2, 3 and 4 ns on a falling edge.
C. Non-blocking assignment of a to b with minimum, typical and maximum delay of 1, 2 and 3ns.
D. Setup time requirements for the flip-flop with output B.
发表于 2009-2-27 00:06:35 | 显示全部楼层
^_^  我遇到过一个公司喜欢考n分频电路 至今没有找到很好的设计
发表于 2009-2-27 08:32:18 | 显示全部楼层

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发表于 2009-2-27 09:52:46 | 显示全部楼层
回头研究一下
发表于 2009-2-27 14:40:45 | 显示全部楼层
thanks,
学习了!!
发表于 2009-2-27 17:28:12 | 显示全部楼层
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